Question 530250
The factors of 32 are 1, 2, 4, 8, 16, and 32.
All of them are powers of 2, so you could say they have 2 as the only factor in their prime factorization.
{{{2^0=1}}}
{{{2^1=2}}}
{{{2^2=4}}} and so on
However, I think 1 did not really count in the mind of the person writing the problem. I don't think they think the prime factorization of 1 involves a 2. Maybe they don't think there is a prime factorization for 1 at all.
Of the factors listed (other than 1), only 4 and 16 are perfect squares.
{{{4=2^2}}} and {{{16=4^2}}}
Four has only one digit, so you could say that the sum of its digits is 4.
What about 16?