Question 530223
Obviously the square root is also an integer.
Let the square root be {{{r}}}
The number is {{{r^2}}}
{{{r^2+2r=323}}}
Completing the square,
{{{r^2+2r+1=324}}}
{{{(r+1)^2=18^2}}}
The solutions to that equation are
{{{r+1=18}}} so that {{{r=17}}} and {{{r^2=289}}} would be the number or
{{{r+1=-18}}} so that {{{r=-19}}}
but obviously that does not work, because by square root of x we usually understand the  positive number that squared equals x.
So, while {{{(-19)^2=361}}} complies with
{{{361+2*(-19)=323}}}, I don't think {{{-19}}}
would be called the square root of {{{361}}}.
We would reserve that name for {{{19}}}