Question 530099
For 3 consecutive odd integers, the sum of the first and third equals twice the middle one.
The same would be true for 3 consecutive integers, or for 3 consecutive even integers, or ...
Back to the problem.
Let the middle integer be {{{n}}}
We know that 3 times the middle one is {{{3n}}}
We know that the sum of the largest and smallest is {{{2n}}}
The problem says that
{{{3n=2n+1}}}
That means that {{{n=1}}}, and the 3 consecutive odd integers are
-1, 1, and 3.
The fact that one of them is negative is odd indeed, but -1 is certainly an integer, and I guess it still qualifies as an odd number. It does not divide evenly by 2.