Question 530049
solve (w+2)^3+88=0 where w is a real number.
:
(w+2)^3 = -88
Find the cube root of both sides
w + 2 = {{{3sqrt(-88)}}}
factor inside the radical to reveal a perfect cube, -8
w + 2 = {{{3sqrt(-8*11)}}}
extract the cube root of -8
w + 2 = {{{-2*3sqrt(11)}}}
subtract 2 from both sides
w = {{{-2*3sqrt(11)}}} - 2