Question 529799
Let l and w be the length and width respectively. Let d be the diagonal.

l = w+2

Then look at this diagram:

<a href="http://s57.photobucket.com/albums/g215/swincher4391/?action=view&amp;current=awesome4.png" target="_blank"><img src="http://i57.photobucket.com/albums/g215/swincher4391/awesome4.png" border="0" alt="Photobucket"></a>

Notice we have a right triangle.

Then w^2 + (w+2)^2 = (10)^2

w^2 + w^2 + 4w + 4 = 100

2w^2 + 4w -96  = 0

2(w^2 + 2w - 48) = 0

2(w+8)(w-6) = 0

w = -8 and w = 6

Can't have a negative width, so  w=6.

Thus our width is 6cm.