Question 529719
Let {{{ s }}} = Staceyville's original population
Let {{{ n }}} = number of years passed
after 1 yr - 2s
after 2 yrs - 4s
after 3 yrs - 8s
{{{ s*2^n }}} is population after {{{n}}} years
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Mc Peakland's population after {{{n}}} yrs is
{{{ 145000*3^n }}}
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given:
{{{ s*2^24 = 145000*3^24 }}}
{{{ s = 145000*(3^24/2^24) }}}
{{{ s = 145000*(3/2)^24 }}}
You can solve this with logs
{{{ log(s) = log(145000) + 24*log( 1.5 ) }}}
{{{ log(s) = log(1.45) + log( 10^5) + 24*log( 1.5 ) }}}
{{{ log(s) = log(1.45) + 5 + 24*log( 1.5 ) }}}
You can finish- can't find calculator