Question 529505
I need help!

A person travels 15 miles in 1/3  of an hour, then returns by traveling that same 15 miles in 1/7  of an hour. What is that person's average rate for the trip?


Average rate = total distance, divided by total time


We then have: {{{(15 + 15)/((1/3) + (1/7))}}}


{{{30/(10/21)}}}, or {{{30(21/10)}}}, or {{{highlight_green(63)}}} mph


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