Question 529656
can you help me solve the system algebraically
y=2(x+3)^2-5
raise to power
2(x^2+6x+9)-5
distribute
y=2x^2+12x+18-5
combine like terms
y=2x^2+12x+13
set to zero
2x^2+12x+13=0
Solve for x using following quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=2, b=12, c=13
ans:
x≈-1.42
or
x≈-4.58