Question 529620
{{{ x^3 -10x^2 + 25x = 0  }}}
{{{ x*(x^2 - 10x + 25) = 0 }}}
Either of these 2 factors must be {{{0}}}, so
{{{ x = 0 }}} is a solution and
{{{ x^2 - 10x + 25 = 0 }}}
This is a perfect square
{{{ ( x + 5 )^2 = 0 }}}
{{{ x = -5 }}} is also a solution
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{{{ 2x^3 - 8x = 0 }}}
{{{ 2x*( x^2 - 8 ) = 0 }}}
{{{ x = 0 }}} is a solution 
also
{{{ x^2 - 8 = 0 }}}
{{{ x = sqrt(8) }}}
{{{ x = 2*sqrt(2) }}} and
{{{ x = -2*sqrt(2) }}}
are both solutions