Question 6448
Use {{{y=2^x}}}. {{{2^2x}}} is {{{(2^x)^2}}}, or {{{y^2}}}.

y^2-24y-256=0

*[invoke quadratic "y", 1, -24, -256]

so, we have 2^x = 32, -8. x=5 makes 2^x equal to 32. Nothing could make 2^x equal to -8. So the answer is x=5.