Question 529346
Let the consecutive odd integers be
{{{ n }}}, {{{ n + 2 }}}, and {{{ n + 4 }}}
given:
{{{ 4n + 3*(n + 4) = 159 }}}
{{{ 4n + 3n + 12 = 159 }}}
{{{ 7n = 147 }}}
{{{ n = 21 }}}
{{{ n + 2 = 23 }}}
{{{ n + 4 = 25 }}}
The numbers are 21, 23, and 25