Question 529053
how would you solve this to graph?
x+3y=3
Plot two points and draw a line thru them:
y = (-1/3)x + 1
If x = 0, y = 1 giving you point (0,1)
If x = 3, y = 0 giving you point (3,0)
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x+y=-3
y = -x-3
If x = 0, y = -3 giving you point (0,-3)
If x = 1, y = -4 giving you point (1,-4)
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{{{graph(400,400,-10,10,-10,10,(-1/3)x+1,-x-3)}}}
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Intersection: (-6,3)
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Cheers,
Stan H.
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