Question 528871
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Use the two point form of an equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Then do the arithmetic to calculate the slope portion of the form: *[tex \Large \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)] resulting in your equation being in the point-slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


After that, perform the necessary manipulations to put your equation into Standard form, namely:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ax\ +\ By\ =\ C]


Multiply through by any fraction denominators to ensure that all of the coefficients are integers.  Not absolutely necessary, but a good idea for neatness sake: If the lead coefficient (the coefficient on *[tex \Large x]) is negative, multiply through by *[tex \Large -1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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