Question 528500


{{{(5x-6)(x+2)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(5x)-6)(highlight(x)+2)}}} Multiply the <font color="red">F</font>irst terms:{{{(5*x)*(x)=5*x^2}}}.



{{{(highlight(5x)-6)(x+highlight(2))}}} Multiply the <font color="red">O</font>uter terms:{{{(5*x)*(2)=10*x}}}.



{{{(5x+highlight(-6))(highlight(x)+2)}}} Multiply the <font color="red">I</font>nner terms:{{{(-6)*(x)=-6*x}}}.



{{{(5x+highlight(-6))(x+highlight(2))}}} Multiply the <font color="red">L</font>ast terms:{{{(-6)*(2)=-12}}}.



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So we have the terms: {{{5*x^2}}}, {{{10*x}}}, {{{-6*x}}}, {{{-12}}} 



{{{5*x^2+10*x-6*x-12}}} Now add every term listed above to make a single expression.



{{{5x^2+4x-12}}} Now combine like terms.



So {{{(5x-6)(x+2)}}} FOILs to {{{5x^2+4x-12}}}.



In other words, {{{(5x-6)(x+2)=5x^2+4x-12}}}.




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