Question 528039
What they mean is:
Get y all by itself on one side of the equation
It doesn't really matter which side
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You do this by doing the same thing to
both sides of the equation, which leaves
the equation unchanged
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{{{ 4y + 12 = -3(2x-4) }}}
Subtract {{{12}}} from both sides
{{{ 4y = -3*(2x-4) - 12 }}}
Now divide both sides by {{{4}}}
{{{ y = (-3/4)*(2x-4) -3 }}}
This is OK, but you can finish by
multiplying out
{{{  (-3/4)*(2x-4) = (-3/2)*x + 3 }}}
Now you have
{{{ y = (-3/2)*x + 3 -3 }}}
{{{ y = (-3/2)*x }}}