Question 528003
h(x)=(5+x)(-6+x)


h(3)=(5+3)(-6+3)


h(3)=(8)(-3)


h(3) = -24

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g(x)=2-x 


g(3)=2-3


g(3) = -1


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(h/g)(x) = (h(x))/(g(x)) 



(h/g)(3) = (h(3))/(g(3))



(h/g)(3) = -24/(-1)



(h/g)(3) = 24


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Since you CANNOT divide by zero, this means that the denominator g(x) cannot be zero.


If it were, then g(x) = 0 would mean that 2-x = 0 and that x = 2



So x = 2 makes the denominator zero. So we must exclude that from the domain.




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