Question 527997
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-2,0\right)]. So this means that {{{x[1]=-2}}} and {{{y[1]=0}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(3,3\right)].  So this means that {{{x[2]=3}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3-0)/(3--2)}}} Plug in {{{y[2]=3}}}, {{{y[1]=0}}}, {{{x[2]=3}}}, and {{{x[1]=-2}}}



{{{m=(3)/(3--2)}}} Subtract {{{0}}} from {{{3}}} to get {{{3}}}



{{{m=(3)/(5)}}} Subtract {{{-2}}} from {{{3}}} to get {{{5}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(-2,0\right)] and *[Tex \LARGE \left(3,3\right)] is {{{m=3/5}}}




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