Question 527990
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-2,3\right)]. So this means that {{{x[1]=-2}}} and {{{y[1]=3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(5,-6\right)].  So this means that {{{x[2]=5}}} and {{{y[2]=-6}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-6-3)/(5--2)}}} Plug in {{{y[2]=-6}}}, {{{y[1]=3}}}, {{{x[2]=5}}}, and {{{x[1]=-2}}}



{{{m=(-9)/(5--2)}}} Subtract {{{3}}} from {{{-6}}} to get {{{-9}}}



{{{m=(-9)/(7)}}} Subtract {{{-2}}} from {{{5}}} to get {{{7}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(-2,3\right)] and *[Tex \LARGE \left(5,-6\right)] is {{{m=-9/7}}}




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