Question 527356
Graph the function. Find the vertex, line of symmetry, and maximum or minimum value.
f(x)=(x+3)^2-4
**
Given equation is that of a parabola of standard form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. Parabola opens upwards, so curve has a minimum.
For given equation:
vertex: (-3,-4)
line of symmetry: x=-3 (a vertical line thru the vertex)
minimum: -4