Question 527595
How do I find the inverse of each function? 
1. y= x^2 + 2 
- switch "y for x" and "x for y":
x= y^2 + 2
- solve for y:
x-2= y^2
sqrt(x-2) = y
y = sqrt(x-2)
.
2. y= x+2 
- switch "y for x" and "x for y":
x= y+2
- solve for y:
y = x-2
.
3. y= 3(x+1) 
- switch "y for x" and "x for y":
x= 3(y+1)
- solve for y:
x= 3(y+1)
x/3= (y+1)
x/3 - 1 = y
y = x/3 - 1