Question 527085
log base8 [(x+8)(x+9)]=2
(x+8)(x+9) = 8^2
x^2+17x+72 = 64
x^2+17x+8 = 0
apply the "quadratic formula" to get:
x = {-0.484, -16.516}
we can throw out the -16.516 (extraneous) leaving:
x = -0.484
.
details of quadratic:

*[invoke quadratic "x", 1, 17, 8 ]