Question 526891
To start off, write the numbers such that they are all in terms of the same number, such as:
x,x+2,x+4,and x+6;since consecutive odd integers are two numbers apart.
Now, if you work backwards, you subtract 40 from the first number:
x-40
and it also says that three times the third plus 10 is the first minus 40, so;
3(x+4)+10=3x+22
so altogether
3x-22=x+40
if you solve, you will get x, which x=31
so the three consecutive odd integers are 31, 31+2, 31+4, and 31+6
or 31,33,35,37