Question 526762
It's not surprising that it doesn't come out right!
Because:
{{{Log(40x+200)}}}is not equal to{{{  Log(40x)+Log(200)}}}
Here's what you must do:
{{{Log(40x+200) = 3}}}  Change this to the exponential form:If {{{Log[b](y) = x}}} then {{{y = b^x}}}
{{{Log(40x+200) = 3}}}---->{{{(40x+200) = 10^3}}} Simplify:
{{{40x+200 = 1000}}} Subtract 200 from both sides.
{{{40x = 800}}} Divide both sides by 40.
{{{x = 20}}}