Question 526391
6x^3 = 3x^2 + 3x
6x^3  - 3x^2 -3x = 0
3x*(2x^2 -x -1) = 0
3x*(2x+1)(x-1) = 0
.
x = 0, -1/2, 1
.
{{{ graph(500,500,-5,5,-5,5,6*x^3-3*x^2-3*x) }}}