Question 526258

Slope of the line passes through (12,6) and (37,13)
m=y2-y1/x2-x1
m=13-6/37-12
m=7/25

Since the lines are parallel their slope will be same.

So required line has a slope 7/25 and passes through the point (8,12)

Standard equation of the line
y=mx+b

slope = m
y-intecept = b

Put the values of slope and points in above equation
12=(7/25)(8)+b
12=56/25+b
12-56/25=b
(300-56)/25=b
244/25=b

Now put the values of b and m in standard equation of the line
y=mx+b
y=(7/25)x+244/25
25y=7x+244