Question 526264
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Presuming you mean "height" which is typically referred to as "width" because I don't know what "hight" means, use the formula for the perimeter:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w]


And then solve for *[tex \Large l] in terms of *[tex \Large P\ ] and *[tex \Large w]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ l\ =\ \frac{P}{2}\ -\ w]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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