Question 526076
The area is 44 square feet, and twice the length is 5 feet shorter than two times the width. What is the perimeter?

Area = A = 4 ft^2
Length = 2l = (2w-5)ft
Length = l = (2w-5)/2 ft
Length = ?
Width = ?

Length * Width = Area of Rectangle
l*w=A
((2w-5)/2)*(w) = 44
(2w^2-5w)/2 = 44
(2w^2-5w) = 44*2
2w^2-5w = 88
2w^2-5w-88=0

*[invoke quadratic "x", 2, -5, -88]

w=-5.5 not possible
w=8



Length = 2l = (2w-5)ft
Length = l = (2w-5)/2 = (2(8)-5)/2=(16-5)/2=11/2=5.5ft


Length = 5.5 ft
Width = 8 ft