Question 525873
{{{(x+9)^2 = 20}}}
{{{x+9=sqrt(20)}}}, or {{{x+9=-sqrt(20)}}}
{{{x[1]=-9+sqrt(20)}}}, {{{x[2]=-9-sqrt(20)}}} the exact solutions

{{{x[1]=-4.528}}}, {{{x[2]=-13.472)}}} the approximate solutions to three decimal places