Question 525652
={{{(5-3i)/(6+2i)}}}
={{{(5-3i)/(6+2i)*(6-2i)/(6-2i)}}}
={{{(30-10i-18i+6i^2)/(6^2-(2i)^2)}}}
={{{(30-28i+6(-1))/(36+4(i)^2)}}}
={{{(30-28i-6)/(36+4(-1))}}}
={{{(24-8i)/(36-4)}}}
={{{(24-8i)/32}}}
={{{8(3-i)/32}}}
={{{(3-i)/4}}}
={{{3/4-i/4}}}