Question 525382
ax^2-1=0

ax^2+0-1=0

a=a,b=0,c=(-1)

x1={{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
{{{x1=(0+sqrt(4a))/(2a)}}}

x1={{{2sqrt(a)/2a}}}

x1={{{(1/(sqrt(a)))}}}