Question 525298
What are four consecutive even integers such that the sum of the first and the third is six less than the largest?


Let the 1st even integer be F


Then others are F + 2, F  + 4, and F + 6


We then have: F + F + 4 = F + 6 - 6


2F + 4 = F


F = - 4


Therefore, the 4 even integers are {{{highlight_green(-4)}}}, {{{highlight_green(-2)}}}, {{{highlight_green(0)}}}, and {{{highlight_green(2)}}}


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Check
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Sum of 1st & 3rd: - 4 + 0, or - 4


Six (6) less than largest: 2 - 6, or - 4


Sum of 1st & 3rd (- 4) = 6 less than largest (- 4)


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