Question 525175
(5xy^2)^3/4
We can say this,"the 4th root of (5xy^2)^3, which is
:
{{{4sqrt((5xy)^3)}}} = {{{4sqrt(5^3*x^3*y^6))}}} = {{{4sqrt(125x^3*y^6))}}}
factor
{{{4sqrt(125x^3*y^4*y^2))}}}
extract the 4th root
{{{y*4sqrt(125x^3*y^2))}}}
:
We can say, "y times the 4th root of 125x^3*y^2"