Question 525048
Shayna left the airport and drove toward the capital at an average speed of 52 km/h.
 Some time later Mei left driving in the same direction but at an average speed of 65 km/h.
 After driving for four hours Mei caught up with Shayna.
 Find the number of hours Shayna drove before Mei caught up
:
Let t = S's travel time when M caught up
:
Find the distance driven by M:
4 * 65 = 260 mi
This is also the distance driven by S, when she is caught
:
52t = 260
t = 260/52
t = 5 hrs, S's travel time when caught by M