Question 525121
Let {{{x}}} is the first integer
then {{{x+1}}} is the second consecutive integer
{{{x(x+1)=30}}}
{{{x^2+x-30=0}}}
{{{(x+6)(x-5)=0}}}
{{{x[1]=-6}}} {{{x[2]=5}}}
{{{x[1]+1=-5}}} {{{x[2]+1=6}}}
Answer {{{-6}}} and {{{-5}}}, or {{{5}}} and {{{6}}}