Question 524860
let the numbers be x & y
x-y=2
x=(y+2)

x^2+y^2=244
(y+2)^2+y^2=244

y^2+4y+4 +y^2=244
2y^2+4y-240=0

/2
y^2+2y-120=0
y^2+12y-10y-120=0
y(y+12)-10(y+12)=0
(y-10)(y+12)=0

y= 10 OR -12

plug values of y in first equation
x-y=2

when y=10 x=12  (12,10)

when y=-12
x=-10
(-10,-12)