<PRE><B>Question 524686</B>
find two consecutive integers such that the sum of 2 times the first integer and 4 times the second integer is 46 
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1st: x
2nd: x+1
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Equation:
2x + 4(x+1) =  46
2x + 4x + 4 = 46
6x + 4 = 46
6x = 42
x = 7
x+1 = 8
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Cheers,
Stan H.
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