<PRE><B>Question 524549</B>
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The sum of the angles in a triangle is 180 degrees.  Hence the sum of B and C has to be 64 degrees (180 minus 116).  Since B is three times C, you can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3C\ +\ C\ =\ 64]


Solve for C.  Then calculate 3C.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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