Question 524241
In order to leave a remainder of 1 when divided by any of
2,3,6,7, and 9, you have to be 1 more than a common multiple
of 2,3,6,7 and 9

2 = 2
3 = 3
6 = 2*3
7 = 7
9 = 3*3

The least common multiple of all those is 2*3*3*7 = 126

The next common multiple of all those is twice that or 252,
which is more than 200.  

But you are less than 200.

So you are 1 more than 126, so you are 127.

Edwin</pre>