Question 524135
With coin problems you have to keep track of the number of coins and the value of the coins.
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d = number of dimes
10d = value of the dimes in cents
q = number of quarters
25q = value of the quarters in cents
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10d cents + 25q cents = 205 cents
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He has 4 more quarters than dimes
q = d+4
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Substitute
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10d + 25(d+4) = 205
10d + 25d + 100 = 205
35d = 105
d = 3
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q = d+4
q = 7
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Check the values to see if this solution is the correct answer.
10(3) = 30 cents
25(7) = 175 cents
30+175 = 205 cents
Correct.
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Answer: 3 dimes and 7 quarters.
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Done.