Question 524123
The basic distance equation is d=r*t
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910 = (s+35) * t, where s = indicated airspeed of the plane and t = time
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760 = (s-49) * t
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We are told t=t
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t = 910/(s+35)
and
t = 760(/(s-49)
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910/(s+35) = 760/(s-49)
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cross multiply
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910*(s-49) = 760*(s+35)
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910s - 44590 = 760s + 26600
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150s = 26600 + 44590 = 71190
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s = 71190/150
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s = 474.6 mph
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Check the times to be sure this answer is correct.
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t = 910/(s+35)
t = 910/(474.6+35)
t = 1.785714285714286
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t = 760(/(474.6-49)
t = 1.785714285714286
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Correct.
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Answer:  With no wind resistance (or assistance) the airplane can fly 474.6 mph.
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Done.