Question 524118
<pre><font size = 4 color = "indigo"><b>

It's obvious that half the possible rolls will have an odd sum
and the other half will have an even sum.  So the probability
is obviously {{{1/2}}}.  Or another way to explain it is:

The rolls colored red below have an odd sum and so the probability
of rolling one of the red rolls is 18 out of the 36 possible rolls 
which is {{{18/36}}} which reduces to {{{1/2}}}:

&#9856;&#9856;   <font color="red">&#9856;&#9857;</font>   &#9856;&#9858;   <font color="red">&#9856;&#9859;</font>   &#9856;&#9860;  <font color="red">&#9856;&#9861;</font>

<font color="red">&#9857;&#9856;</font>   &#9857;&#9857;   <font color="red">&#9857;&#9858;</font>   &#9857;&#9859;   <font color="red">&#9857;&#9860;</font>  &#9857;&#9861;

&#9858;&#9856;   <font color="red">&#9858;&#9857;</font>   &#9858;&#9858;   <font color="red">&#9858;&#9859;</font>   &#9858;&#9860;  <font color="red">&#9858;&#9861;</font>

<font color="red">&#9859;&#9856;</font>   &#9859;&#9857;   <font color="red">&#9859;&#9858;</font>   &#9859;&#9859;   <font color="red">&#9859;&#9860;</font>  &#9859;&#9861;

&#9860;&#9856;   <font color="red">&#9860;&#9857;</font>   &#9860;&#9858;   <font color="red">&#9860;&#9859;</font>   &#9860;&#9860;  <font color="red">&#9860;&#9861;</font>

<font color="red">&#9861;&#9856;</font>   &#9861;&#9857;   <font color="red">&#9861;&#9858;</font>   &#9861;&#9859;   <font color="red">&#9861;&#9860;</font>  &#9861;&#9861;

Edwin</font></b>