<PRE><B>Question 523971</B>
in a certain triangle the measure of the measure of the second angle is 10 degrees greater than three times the first. the third angle measure is equal to the sum of the measures of the other two. Find the measures of the three angles.
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let x=measure of first angle
3x+10=measure of second angle
x+(3x+10)=measure of third angle
..
x+(3x+10)+(x+(3x+10))=180
x+3x+10+x+3x+10=180
8x=180-20=160
x=20º
ans:
measure of first angle=20º
measure of second angle=70º
measure of third angle=90º</PRE>