Question 523758
One leg				3	in				
Second leg				6	in				
Hypotenuse 				x 	in				
By Pythagoras theorem 									
Hypotenuse^2 = Leg1^2+leg2^2									
{{{ 	x 	^2	=	3	^2	+	6	^2}}}	
x 	^2	=	9	+	36				
x 	^2	=	45						
{{{ sqrt(x^2)=		sqrt(	45	)}}}					
x=	6.71	in							
									
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