Question 523675
How long it will take for an investment of 2000 dollars to double in value if the interest rate is 10 percent per year, compounded continuously?
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A(t) = P*e^(rt)
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4000 = 2000*e^(0.1*t)
2 = e^ (0.1t)
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Take the natural log of both sides to get:
0.1t = ln(2)
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t = 0.6931/0.1
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t = 6.931 years
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Cheers,
Stan H.
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