Question 523644
Given the line has slope -2/3 we can define the equation using slope-intercept form:
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y = -2/3x + b
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Use the point to find 'b'.
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12 = -(2/3)*6 + b
12 = -4 + b
16 = b
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So the equation is:
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y = -2/3x + 16
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{{{ graph(500,500,-5,25,-5,25,-2/3*x+16) }}}