Question 523644
the line has a slope of -2/3 and passes through (6,12)
.
Plug into "point-slope" form:
y - y1 = m(x - x1)
y - 12 = (-2/3)(x - 6)
y - 12 = (-2/3)x + 4
y = (-2/3)x + 16 (this is what they're asking for... in "slope-intercept")