Question 52073
I am assuming that you have to find the equation of the line that meets those requirements.

Put the line in slope intercept form (y=mx+b)  
m=slope and (0,b)=y-intecept
A line that is perpendicular to this one would have a slope that in the negative reciprocal of this slope (-1/m)
4x-y=6
-4x+4x-y=-4x+6
0-y=-4x+6
-y=-4x+6
-1(-y)=-1(-4x+6)
y=4x-6
The slope (m) of this line is 4 the slope of a line that is perpendicular to this line (-1/m) is -1/4.
The y intercept (b=-6) is the same, so the answer is:
y=-1/4x-6