Question 523104
Solve the equation on the interval 0 < theta < 2pi 
cot 2theta/3 = -sqrt3
**
using x in place of theta
cot(2x/3)=-&#8730;3
2x/3=5&#960;/6 and 11&#960;/6 (reference angles of &#960;/6 in quadrants II and IV where cot<0)
2x/3=5&#960;/6
2x=15&#960;/6
x=15&#960;/12=5&#960;/4
and
2x/3=11&#960;/6
2x=33&#960;/6
x=33&#960;/12=11&#960;/4