<PRE><B>Question 523083</B>
{{{(3a-5)^3}}}
which is
(3a-5)*(3a-5)*(3a-5)
First FOIL (3a-5)(3a-5)
9a^2 - 5a - 5a + 25
9a^2 - 10a + 25
Multiply this by (3a-5), using the old method of multiplying you learned in grade school.
9a^2 - 10a + 25
. . X . . 3a - 5
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you should get
27a^3 - 75a^2 + 125a - 125</PRE>