Question 522526
Can you please help me with a problem? i have to identify the conic section and write the standard form and then graph it. x^2+y^2-4y-5=0   
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x^2+y^2-4y-5=0
complete the square
x^2+(y^2-4y+4)=5+4=9
x^2+(y-2)^2=9
This is an equation of a circle of standard form: (x-h)^2+(y-k)^2=r^2, (h,k)=center, r=radius.
For given equation:
center: (0,2)
radius=√9=3
see graph below:
..
y=±
{{{ graph( 300, 300, -10, 10, -10, 10,(9-x^2)^.5+2,-(9-x^2)^.5+2) }}}